2*4x^-3=16x/8x^-1

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Solution for 2*4x^-3=16x/8x^-1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*4*x^-3 = x^-1*((16*x)/8) // - x^-1*((16*x)/8)

2*4*x^-3-(x^-1*((16*x)/8)) = 0

2*4*x^-3-2 = 0

8*x^-3 = 2 // : 8

x^-3 = 1/4

-3 < 0

1/(x^3) = 1/4 // * x^3

1 = 1/4*x^3 // : 1/4

4 = x^3

x^3 = 4 // ^ 1/3

x = 4^(1/3)

x = 4^(1/3)

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